Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Probability

Question:

A die is thrown again and again until three sixes are obtained. The probability of obtaining third six in sixth throw of the die is :

Options:

$\frac{1}{23328}$

$\frac{625}{23328}$

$\frac{25}{36}$

$\frac{25}{23328}$

Correct Answer:

$\frac{625}{23328}$

Explanation:

The correct answer is Option (2) → $\frac{625}{23328}$

P to obtain 3rd six in sixth throw

$={^5C}_2×(\frac{1}{6})^2(\frac{5}{6})^3×\frac{1}{6}$

$=\frac{625}{23328}$