Practicing Success
A die is thrown again and again until three sixes are obtained. The probability of obtaining third six in sixth throw of the die is : |
$\frac{1}{23328}$ $\frac{625}{23328}$ $\frac{25}{36}$ $\frac{25}{23328}$ |
$\frac{625}{23328}$ |
The correct answer is Option (2) → $\frac{625}{23328}$ P to obtain 3rd six in sixth throw $={^5C}_2×(\frac{1}{6})^2(\frac{5}{6})^3×\frac{1}{6}$ $=\frac{625}{23328}$ |