A die is thrown again and again until three sixes are obtained. The probability of obtaining third six in sixth throw of the die is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{625}{23328}$
P to obtain 3rd six in sixth throw
$={^5C}_2×(\frac{1}{6})^2(\frac{5}{6})^3×\frac{1}{6}$
$=\frac{625}{23328}$