If A is 48% more than B and C is 60%less than the sum of A and B, then A is what percentage more than C? (Correct to one decimalplace.)
Answer & explanation
Correct answer: option 3
48% = \(\frac{12}{25}\) , 60% = \(\frac{3}{5}\)
A : B
37 : 25
ATQ , C = \(\frac{2}{5}\) × 62 = 24.8
A is more than C by ( percentage ) = \(\frac{37 - 24.8}{24.8}\) × 100
= 49.19%
= 49.2% ( approx)