If A is 48% more than B and C is 60%less than the sum of A and B, then A is what percentage more than C? (Correct to one decimalplace.)

49.2

48% = \(\frac{12}{25}\) , 60% = \(\frac{3}{5}\)

 A    :   B

 37  :   25

ATQ , C = \(\frac{2}{5}\) × 62 = 24.8

A is more than C by ( percentage ) = \(\frac{37 - 24.8}{24.8}\)  × 100

= 49.19%

= 49.2%     ( approx)