If tanθ = 8/15 find the value of (24cotθ +1)/(34cosθ-1) .

tanθ = \(\frac{8}{15}\) = \(\frac{P}{B}\) (Triplet 8 , 15 , 17)

H = 17

Put than and find

⇒ \(\frac{24cotθ +1}{34cosθ-1}\)

⇒ \(\frac{24×\frac{15}{8} +5}{34\frac{15}{17} - 1}\) 

⇒ \(\frac{45 + 5 }{30 -1}\) 

⇒ \(\frac{50}{29}\)