If tanθ = \(\frac{8}{15}\) find the value of \(\frac{24cotθ +1}{34cosθ-1}\) .

\(\frac{29}{50}\)   \(\frac{50}{29}\)   \(\frac{3}{29}\)   \(\frac{55}{29}\)

\(\frac{50}{29}\)

tanθ = \(\frac{8}{15}\) = \(\frac{P}{B}\) (Triplet 8 , 15 , 17) H = 17 Put than and find ⇒ \(\frac{24cotθ +1}{34cosθ-1}\) ⇒ \(\frac{24×\frac{15}{8} +5}{34\frac{15}{17} - 1}\)  ⇒ \(\frac{45 + 5 }{30 -1}\)  ⇒ \(\frac{50}{29}\)