If \(|\vec{a}+\vec{b}|=|\vec{a}|+|\vec{b}|\) where \(\vec{a}\) and \(\vec{b}\) are any vectots, then this equality
Answer & explanation
Correct answer: option 3
\(|\vec{A}+\vec{b}|=|\vec{a}|+|\vec{b}|\) thus \(\vec{a}\) and \(\vec{b}\) are scalar multiple of each other so \(\vec{a}=k\vec{b}\)