$\Delta=\left|\begin{array}{ccc}p & 2-i & i+1 \\ 2+i & q & 3+i \\ 1-i & 3-i & r\end{array}\right|$ is always
Answer & explanation
Correct answer: option 1
Since $\Delta=\bar{\Delta} \quad ∴ \Delta$ is real only
Hence (1) is the correct answer
$\Delta=\left|\begin{array}{ccc}p & 2-i & i+1 \\ 2+i & q & 3+i \\ 1-i & 3-i & r\end{array}\right|$ is always
Correct answer: option 1
Since $\Delta=\bar{\Delta} \quad ∴ \Delta$ is real only
Hence (1) is the correct answer