If a ball is thrown vertically upwards with speed u, the distance covered during the last t seconds of its ascent is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{1}{2}gt^2$
The time taken by the ball to reach the highest point
$=u –gn ⇒n=\frac{u}{g}$
$S_n=un-\frac{1}{2}gn^2$
and $S_{n-t}=u(n-t)-\frac{1}{2}g(n-t)^2$
$∴ s =S_n-S_{n-t}=\frac{1}{2}gt^2$