A TV manufacturer tests a random sample of a 6 picture tubes to determine any defect. Past experience suggests the probability of defective picture tube is 0.05. The probability that there is at least one defective picture in the sample is:

$\left(\frac{19}{20}\right)^6$ $1-\left(\frac{19}{20}\right)^6$ $1-\left[\left(\frac{19}{20}\right)^6+\frac{3}{10}\left(\frac{9}{20}\right)^5\right]$ $\left(\frac{1}{20}\right)^6$

$1-\left(\frac{19}{20}\right)^6$

The correct answer is Option (2) → $1-\left(\frac{19}{20}\right)^6$