Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

Velocity v, acceleration a and force f are taken as fundamental quantities, then angular momentum will have the dimension :

Options:

fv2a-2

f2v2a-2

fv3a-2

None of these

Correct Answer:

fv2a-2

Explanation:

Angular momentum (L) ∝ vx ay fz

ML2T-1 = (LT-1)x (LT-2)y (MLT-2)z

ML2T-1 = Mz Lx+y+z T-x-2y-2z

1 = z

2 = x + y + z ⇒ x + y = 1

-1 = -x - 2y - 2z ⇒ x + 2y = 1 - 2 = -1

∴ y = -2

x + y = 1

⇒ x = -y = 2

∴ Angular momentum (L) =  v2 a -2 f