\(\int 2^{2^{x}}2^xdx=\)1\(2^x\log 2+c\)2\(2^{2^x}\frac{1}{(\log2)^2}+c\)3\(2^{2^x}\log 2+c\)4\(2^x(\log 2)^2+c\)Answer & explanation+Correct answer: option 2Put \(2^{2^x}=t\)
