\(\int 2^{2^{x}}2^xdx=\)

\(2^x\log 2+c\) \(2^{2^x}\frac{1}{(\log2)^2}+c\) \(2^{2^x}\log 2+c\) \(2^x(\log 2)^2+c\)

\(2^{2^x}\frac{1}{(\log2)^2}+c\)

Put \(2^{2^x}=t\)