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If a, b and c are positive integers such that $a^2 + b^2 = 82$ and $b^2 + c^2 = 65$, then the value of 2a + 7b − 3c is: |
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$a^2 + b^2 = 82$ $b^2 + c^2 = 65$, Then the value of 2a + 7b − 3c = ? Put the value of a = 9 , b = 1 and c = 8 2a + 7b − 3c = 2×9 + 7×1 − 3×8 = 18 + 7 - 24 2a + 7b − 3c = 1 |
