Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

A physical quantity of the dimensions of length that can be formed out of c, G and \(\frac{e^2}{4 \pi \epsilon_o}\) [c is velocity of light, G is universal constant of gravitation and e is charge]

Options:

\(\frac{1}{c}\) G \(\frac{e^2}{4 \pi \epsilon_o}\)

\(\frac{1}{c^2}\) [G \(\frac{e^2}{4 \pi \epsilon_o}\)]1/2

c2 [G \(\frac{e^2}{4 \pi \epsilon_o}\)]2

\(\frac{1}{c^2}\) [\(\frac{e^2}{4 G \pi \epsilon_o}\)]2

Correct Answer:

\(\frac{1}{c^2}\) [G \(\frac{e^2}{4 \pi \epsilon_o}\)]1/2

Explanation:

G = M-1 L3 T-2

c = L1 T-1

\(\frac{e^2}{4πε_o}\) = M1 L3 T-2

l ∝ cP GQ [\(\frac{e^2}{4πε_o}\)]R 

l ∝ LP T-P (M-1 L3 T-2)Q (M1 L3 T-2)R

M0 L1 T0 = M-Q+R LP+3Q+3R T-P-2Q-2R

-Q + R = 0

Q = R

P+3Q+3R = 1

-P-2Q-2R = 0

On solving, Q = R = \(\frac{1}{2}\), P = -2

l ∝ \(\frac{1}{c^2}\) [G \(\frac{e^2}{4 \pi \epsilon_o}\)]1/2