If $x^2+y^2=1$, then
Answer & explanation
Correct answer: option 2
We have,
$x^2+y^2=1$
Differentiating w.r.t. x, we get
$2 x+2 y y'=0 \Rightarrow x+y y'=0$
Again differentiating w. r. t. x, we get
$1+\left(y'\right)^2+y y''=0$
If $x^2+y^2=1$, then
Correct answer: option 2
We have,
$x^2+y^2=1$
Differentiating w.r.t. x, we get
$2 x+2 y y'=0 \Rightarrow x+y y'=0$
Again differentiating w. r. t. x, we get
$1+\left(y'\right)^2+y y''=0$