What is the area (in sq cm) of a regular hexagon of side 14 cm?

294√3

Area of regular hexagon = 6 × area of one equilateral triangle.

                                       = 6 × \(\frac{\sqrt{3}}{4}\) a²

                                       = 6 × \(\frac{\sqrt{3}}{4}\) 14²

                                       = 6 × \(\frac{\sqrt{3}}{4}\) × 196

                                       = 294 \(\sqrt{3}\)