Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

Find the ratio of mean proportion of 10.8 and 4.8 to the 3rd proportion of 0.4 and 2.4.

Options:

2 : 1

2 : 3

1 : 2

3 : 2

Correct Answer:

1 : 2

Explanation:

Let x is the mean proportion and

y is 3rd proportion

Here,

Mean proportion = \(\sqrt {a\;×\;b}\)

⇒ x = \(\sqrt{4.8\;×\;10.8}\) = 7.2, and

3rd proportion = \(\frac{b^2}{a}\)

y =  \(\frac{2.4×2.4}{0.4}\) = 14.4

x  :  y  = 7.2  :  14.4 = 1  :  2