CUET Preparation Today
The molality of solution obtained by dissolving 1.5 g of ethanoic acid $(CH_3COOH)$ in 25g of benzene is: |
$0.1\, mol\, kg^{-1}$ $0.001\, mol\, kg^{-1}$ $1.0\, mol\, kg^{-1}$ $0.2\, mol\, kg^{-1}$ |
$1.0\, mol\, kg^{-1}$ |
The correct answer is Option (3) → $1.0\, mol\, kg^{-1}$ |
