If tan θ + sec θ = 2 ; what is the value of tanθ.secθ ?
Answer & explanation
Correct answer: option 3
tan θ + sec θ = 2
⇒ secθ - tan θ = \(\frac{1}{2}\)
4tanθ.secθ = (tanθ + secθ) 2 - (secθ - tanθ) 2
⇒ 4tanθ.secθ = 2 2 - \(\frac{1}{2^2}\)
⇒ tanθ.secθ = \(\frac{1}{4}\)(4 - \(\frac{1}{4}\)) = \(\frac{15}{16}\)