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If tan θ + sec θ = 2 ; what is the value of tanθ.secθ ? |
0 1 \(\frac{15}{16}\) \(\frac{16}{15}\) |
\(\frac{15}{16}\) |
tan θ + sec θ = 2 ⇒ secθ - tan θ = \(\frac{1}{2}\) 4tanθ.secθ = (tanθ + secθ) 2 - (secθ - tanθ) 2 ⇒ 4tanθ.secθ = 2 2 - \(\frac{1}{2^2}\) ⇒ tanθ.secθ = \(\frac{1}{4}\)(4 - \(\frac{1}{4}\)) = \(\frac{15}{16}\) |
