CUET Preparation Today
CUET
-- Mathematics - Section B1
Continuity and Differentiability
If f(x) = |x - 25| and g(x) = f(f(x)) then for x > 50, g'(x) is equal to
0
1
25
None of these
g(x) = f(f(x)) = f(|x - 25|) = ||x - 25|- 25|
and for x > 50, g(x) = |x - 25 - 25| = |x – 50| = x - 50
⇒ g'(x) = 1.
Hence (B) is the correct answer.