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The length of hypotenuse of a right angle isosceles triangle is 10 cm. Its area will be: |
25\(\sqrt {2}\) sq. cm 50 sq. cm 25 sq. cm 100 sq. cm |
25 sq. cm |
In Δ ABC: ⇒ AB2 + BC2 = AC2 ⇒ x2 + x2 = 100 ⇒ 2x2 = 100 ⇒ x2 = 50 Area = \(\frac{1}{2}\) × x2 = \(\frac{1}{2}\) × 50 = 25 sq.cm |
