If $X - \frac{1}{x} = 13$, what will be the value of $X^4 +\frac{1}{x^4}$?
Answer & explanation
Correct answer: option 4
If $X - \frac{1}{x} = 13$
Then ,
x + \(\frac{1}{x}\) = \(\sqrt {13^2 + 4}\) = \(\sqrt {173}\)
then x2 + \(\frac{1}{x^2}\) = (\(\sqrt {173}\))2 - 2 = 171
and x4 + \(\frac{1}{x^4}\) = 1712 - 2 = 29239