If $X - \frac{1}{x} = 13$, what will be the value of $X^4 +\frac{1}{x^4}$?

28561 29243 27887 29239

29239

If $X - \frac{1}{x} = 13$ Then , x + \(\frac{1}{x}\) = \(\sqrt {13^2 + 4}\) =  \(\sqrt {173}\) then x2 + \(\frac{1}{x^2}\) = (\(\sqrt {173}\))2 - 2 = 171 and x4 + \(\frac{1}{x^4}\) = 1712 - 2 = 29239