The values of $\lambda$ for which the following system of equations has unique solution.
$\lambda x+3 y-z=1$
$x+2 y+z=2$
$-\lambda x+y+2 z=-1$ are
Answer & explanation
Correct answer: option 4
$\lambda x+3 y-z=1$ ......(1)
$x+2 y+z=2$ ......(2)
$-\lambda x+y+2 z=-1$ ......(3)
so $A=\left[\begin{array}{ccc}\lambda & 3 & -1 \\ 1 & 2 & 1 \\ -\lambda & 1 & 2\end{array}\right]$
for unique solution
$|A| \neq 0$
so $|A|=\left|\begin{array}{ccc}\lambda & 3 & -1 \\ 1 & 2 & 1 \\ -\lambda & 1 & 2\end{array}\right|$
so $|A|=\lambda\left|\begin{array}{ll}2 & 1 \\ 1 & 2\end{array}\right|-3\left|\begin{array}{cc}1 & 1 \\ -\lambda & 2\end{array}\right|-1\left|\begin{array}{cc}1 & 2 \\ -\lambda & 1\end{array}\right|$
upon solving
$|A|=-2 \lambda-7 \neq 0$
$\Rightarrow 2 \lambda \neq-7$
$\lambda \neq \frac{-7}{2}$