Inner transition Elements
The lanthanoid contraction is a feature of f block elements in which overall decrease in atomic radii from lanthanum to lutetium is observed. The decrease in atomic radii is not quite regular as it is regular in M3+ ions. This is because of imperfect shielding of one electron by another in the same subshell. The shielding of one 4f electron by another is less than one d electron by another with the increase in nuclear charge along the series. In the lanthanoid La(II) and Ln(III) are predominant species. Occasionally +2 and +4 ions in solution or in solid compounds are obtained. The formation of CeIV is favored by its noble gas configuration but it acts like a strong oxidising agent reverting to the common +3 state. The E0 value for CeIV/CeIII is +1.74 V which refer that it can oxidise water. The Pr, Nd, Tb and Dy show +4 state in oxides only. Eu2+ is a strong reducing agent changing to the common +3 state. Actinoids include 14 elements from Th to Lr. There is gradual decrease in size of atoms or M3+ ions in series and referred as actinoid contraction. The contraction is greater from element to element in this series resulting from poor shielding by 5f electrons.
Zr and Hf possess almost identical radii because of
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → Lanthanoid contraction
Down a group of transition elements, the atomic radius normally increases because a new shell is added. It does so from the 3d to the 4d series. But between the 4d and 5d series, the 14 lanthanoids (filling 4f) come in. Their steady contraction cancels the expected increase.
So Zr (4d series) and Hf (5d series) of group 4 have almost identical radii, because of the lanthanoid contraction.
NCERT (2026-27 edition):
Atomic and Ionic Sizes – …
