In the given transistor circuit, the base current is 35 μA. the value of Rb is

200 kΩ

Given that,

$I_L = 35 μA = 85 × 10^{−6} A$

and voltage in the circuit = 7 volt

We know that resistance offered by the junction in forward bias is zero.

Since, the base emitter junction is forward biased therefore junction resistance is almost zero. We also know that the base resistance

$R_b = \frac{V}{I_b}=\frac{7}{35×10^{-6}}$

$R_b = 200 kΩ$