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Home Questions 8EZFHV4R49
Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Solutions

Question:

Match the entries of column I with appropriate entries of column II and choose the correct option out of the four options given.

Column I Column II
(i) Mass percentage (a) \(\frac{\text{No. of moles of solute}}{\text{Volume of solution in litres}}\)
(ii) Molality (b) \(\frac{\text{No. of moles of a component}}{\text{Total number of moles of all the components}}\)
(iii) Mole fraction (c) \(\frac{\text{Mass of the solute component in solution}}{\text{Total mass of solution}}\)
(iv) Molarity (d) \(\frac{\text{No. of moles of solute}}{\text{Mass of solvent in kilograms}}\)

 

Options:

(i)-(d), (ii)-(c), (iii)-(a), (iv)-(b)

(i)-(c), (ii)-(d), (iii)-(b), (iv)-(a)

(i)-(a), (ii)-(d), (iii)-(b), (iv)-(c)

(i)-(c), (ii)-(b), (iii)-(d), (iv)-(a)

Correct Answer:

(i)-(c), (ii)-(d), (iii)-(b), (iv)-(a)

Explanation:

The correct answer is option 2. (i)-(c), (ii)-(d), (iii)-(b), (iv)-(a).

Column I Column II
(i) Mass percentage (c) \(\frac{\text{Mass of the solute component in solution}}{\text{Total mass of solution}}\)
(ii) Molality (d) \(\frac{\text{No. of moles of solute}}{\text{Mass of solvent in kilograms}}\)
(iii) Mole fraction (b) \(\frac{\text{No. of moles of a component}}{\text{Total number of moles of all the components}}\)
(iv) Molarity (a) \(\frac{\text{No. of moles of solute}}{\text{Volume of solution in litres}}\)

Let us go into detail to explain the matching of entries in Column I with appropriate entries in Column II:

(i) Mass percentage (c):

Mass percentage is the percentage of the total mass of a solution that is attributable to a particular component (usually the solute). It is calculated using the formula:
\(\text{Mass percentage} = \frac{\text{Mass of the solute component in solution}}{\text{Total mass of solution}} \times 100 \)

(ii) Molality (d):

Molality is a measure of the concentration of a solution in terms of the number of moles of solute per kilogram of solvent. The formula for molality is:

\(\text{Molality} = \frac{\text{No. of moles of a component}}{\text{Mass of solvent in kilograms}} \)

(iii) Mole fraction (b):

Mole fraction is the ratio of the number of moles of a particular component to the total number of moles of all components in a solution. The formula for mole fraction is:
  \[ \text{Mole fraction} = \frac{\text{No. of moles of a component}}{\text{Total number of moles of all the components}}\]

(iv) Molarity (a):

Molarity is a measure of the concentration of a solution in terms of the number of moles of solute per liter of solution. The formula for molarity is:

\(\text{Molarity} = \frac{\text{No. of moles of solute}}{\text{Volume of solution in litres}}\)

So, in summary:

(i) Mass percentage corresponds to (c) \(\frac{\text{Mass of the solute component in solution}}{\text{Total mass of solution}}\)

(ii) Molality corresponds to (d) \(\frac{\text{No. of moles of a solute}}{\text{Mass of solvent in kilograms}}\)

(iii) Mole fraction corresponds to (b) \(\frac{\text{No. of moles of a component}}{\text{Total number of moles of all the components}}\)

(iv) Molarity corresponds to (a) \(\frac{\text{No. of moles of solute}}{\text{Volume of solution in litres}}\)

This corresponds to option 2 (i)-(c), (ii)-(d), (iii)-(b), (iv)-(a).

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