Practicing Success
A photon of energy E ejects a photoelectron from a metal surface whose work function is 0W If electron having maximum kinetic energy enters into a uniform magnetic field of induction B in a direction perpendicular to the field and describes a circular path of radius r, then the radius r is given by, (in the usual notation): |
$\frac{\sqrt{2m(E-W_0)}}{eB}$ $\sqrt{2m(E-W_0)eB}$ $\frac{\sqrt{2m(E-W_0)}}{mB}$ None of these |
$\frac{\sqrt{2m(E-W_0)}}{eB}$ |
As, $\frac{mv^2}{r}=qvB⇒\frac{mv}{qB}=r$ Also, $mv=P⇒P=\sqrt{2mk}$ $⇒r=\frac{\sqrt{2mk}}{Bq}=\frac{\sqrt{2m(E-W_0)}}{eB}$ |