$\int\left(x^6+x^4\right) d\left(x^2\right)$ is equal to:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{x^8}{4}+\frac{x^6}{3}+C$, where C is a constant
$\int x^6+x^4d(x^2)$
so $\int 2(x^6+x^4)x\,dx=2\left(\frac{x^8}{8}+\frac{x^6}{6}\right)+c$
$=\frac{x^8}{4}+\frac{x^6}{3}+c$