Calculate the dispersive power for crown

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Target Exam

CUET

Subject

Physics

Chapter

Ray Optics

Question:

Calculate the dispersive power for crown glass from the given data $μ_v =1.523$ and $μ_R =1.5145$

Options:

0.1639

0.01639

1.639

2.639

Correct Answer:

0.01639

Explanation:

Here $μ_v = 1.523$ and $μ_R = 1.5145$

Mean refractive index $μ = \frac{1.523−1.5145}{(1.51875−1)} = 0.01639$

Dispersive power $ω$ is given by,

$ω= μ_v − μ_R (μ − 1) = \frac{1.523 − 1.5145}{ (1.51875 −1)}= 0.01639$