CUET Preparation Today
Calculate the dispersive power for crown glass from the given data $μ_v =1.523$ and $μ_R =1.5145$ |
0.1639 0.01639 1.639 2.639 |
0.01639 |
Here $μ_v = 1.523$ and $μ_R = 1.5145$ Mean refractive index $μ = \frac{1.523−1.5145}{(1.51875−1)} = 0.01639$ Dispersive power $ω$ is given by, $ω= μ_v − μ_R (μ − 1) = \frac{1.523 − 1.5145}{ (1.51875 −1)}= 0.01639$ |
