If sec θ + tan θ = 3, then what is the value of sec θ - tan θ ?

sec θ + tan θ = 3

{ we know,

sec² θ - tan² θ = 1

And sec θ - tan θ = \(\frac{1}{sec θ + tan θ}\) }

so,   sec θ - tan θ = \(\frac{1}{3}\)