The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is :
Answer & explanation
Correct answer: option 3
Escape velocity : ve = \(\sqrt{\frac{2 G M}{R}}\)
M = \(\frac{4 \pi}{3} \rho\) R3
ve = \(\sqrt{\frac{8 \pi G \rho}{3}}\) R
∴ ve ∝ R
v/v' = R/4R