Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

The escape velocity from the Earth's surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is : 

Options:

2v

3v

4v

v

Correct Answer:

4v

Explanation:

Escape velocity : ve = \(\sqrt{\frac{2 G M}{R}}\) 

M = \(\frac{4 \pi}{3} \rho\) R3

ve = \(\sqrt{\frac{8 \pi G \rho}{3}}\) R

∴ ve ∝ R

v/v' = R/4R