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If $f(x)=\frac{3x+2}{5x-3}, x\in R -\begin{Bmatrix} \frac{3}{5}\end{Bmatrix},$ then |
$f^{-1}(x)=f(x)$ $f^{-1}(x)=-f(x)$ $f(f(x))=-x$ $f^{-1}(x)=\frac{1}{7}f(x)$ |
$f^{-1}(x)=f(x)$ |
$f(x)=\frac{3x+2}{5x-3}$, $y=\frac{3x+2}{5x-3}$ so $5xy-3y=3x+2$ so $5xy-3x=3y+2$ so $x(5y-3)=3y+2$ so $x=\frac{3y+2}{5y-3}=f^{-1}(y)⇒f^{-1}(x)=\frac{3x+2}{5x-3}$ so $f(x)=f^{-1}(x)$ |
