At room temperature, if the relative permittivity of water be 80 and the velocity of light in water is 2.25 x 10⁸ ms^-1, then what is the relative permeability of water ?

0.022

Expressions: 

μ = = \(\frac{1}{v^{2}ε}\)

c = 1/\(\sqrt { \mu_{o} }\epsilon_{o} \)

μ_r = μ/μ_o ⇒ μ = μ_rμ_o

ε_r = ε/ε_o ⇒  ε = ε_rε_o

ε_r = 80 ; v = 2.25 x 10⁸ ms^-1 ; c = 3.0 x 10⁸ ms^-1 

μ_r  = 0.022