Find the area of regular hexagon whose side is 6 cm long.

54\(\sqrt{3}\) sq. cm

Area of Regular hexagon = 6 × area of one equilateral triangle

                                        = 6 × \(\frac{\sqrt {3}}{4}\)a²

                                        = 6 × \(\frac{\sqrt {3}}{4}\) × 6²

                                        = 54\(\sqrt {3}\) cm²