Find the area of regular hexagon whose side is 6 cm long.

54 sq. cm 36\(\sqrt{12}\) sq. cm 54\(\sqrt{3}\) sq. cm 60 sq. cm

54\(\sqrt{3}\) sq. cm

Area of Regular hexagon = 6 × area of one equilateral triangle                                         = 6 × \(\frac{\sqrt {3}}{4}\)a2                                         = 6 × \(\frac{\sqrt {3}}{4}\) × 62                                         = 54\(\sqrt {3}\) cm2