What is the value of $\frac{(a+b)^2 -(a -b)^2}{ab}$?
Answer & explanation
Correct answer: option 2
$\frac{(a+b)^2 -(a -b)^2}{ab}$ = ?
Put the value of a and b = 1
$\frac{(a+b)^2 -(a -b)^2}{ab}$ = $\frac{(1+1)^2 -(1 -1)^2}{1}$ = 4
What is the value of $\frac{(a+b)^2 -(a -b)^2}{ab}$?
Correct answer: option 2
$\frac{(a+b)^2 -(a -b)^2}{ab}$ = ?
Put the value of a and b = 1
$\frac{(a+b)^2 -(a -b)^2}{ab}$ = $\frac{(1+1)^2 -(1 -1)^2}{1}$ = 4