A and B together can complete the same work in 36 days. B and C together can complete the same work in 60 days. A and C together can complete the same work in 45 days. In how many days, B alone can complete the same work?
Answer & explanation
Correct answer: option 4
A + B = 36 days,
B + C = 60 days,
C + A = 45 days,
⇒ Adding all the efficiencies, we get,
⇒ 2(A + B + C) = 12,
⇒ A + B + C = 6, (Efficiency)
⇒ 5 + C = 6,
⇒ C = 1,
Similarly,
⇒ B + C = 3,
⇒ B + 1 = 3,
⇒ B = 2,
⇒ Time required by B to complete the work alone = \(\frac{180}{2}\) = 90 days, ..(\(\frac{Work}{Efficiency}\) = Time)