Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electric Charges and Fields

Question:

Dimension of Permittivity is :

Options:

[ML-2T2A3]

[M-1L-3T4A-2]

[M0L0T0A0]

[M-1L-3T4A2]

Correct Answer:

[M-1L-3T4A2]

Explanation:

$ F = \frac{1}{4\pi\epsilon_0} \frac{q^2}{r^2}$

 Dimension of $\Rightarrow [\epsilon_0] = \frac{q^2}{4\pi Fr^2} = [M^{-1}L^{-3}T^4A^2]$