If $f(x)=\left\{\begin{matrix}ax^2+b,&x≤0\\0,&x>0\end{matrix}\right.$ is differentiable at x = 0, then
Answer & explanation
Correct answer: option 3
For continuity at x = 0, b = 0
For differentiability 2ax = 0 at x = 0
So a can be any real number , b = 0