CUET Preparation Today
Solve the following. $\frac{24÷\frac{3}{8}\, of\,(8+2×\overline{7-3})+\begin{bmatrix}\frac{2}{11}÷\frac{4}{55}−\begin{Bmatrix}\frac{5}{8}+\frac{6}{16}\end{Bmatrix}\end{bmatrix}}{32÷\overline{15−7}+75÷(6+15÷3+4)}$ |
$\frac{23}{27}$ $\frac{9}{2}$ $\frac{11}{18}$ $\frac{15}{19}$ |
$\frac{11}{18}$ |
