A particle moves in a circle of radius 5cm with constant speed and time period 0.2πs. The acceleration of the particle is :
Answer & explanation
Correct answer: option 1
a = \(\omega^2R = [\frac{2\pi}{0.2\pi}]^2 × (5×10^{-2})\)
a = 5 m/s2
A particle moves in a circle of radius 5cm with constant speed and time period 0.2πs. The acceleration of the particle is :
Correct answer: option 1
a = \(\omega^2R = [\frac{2\pi}{0.2\pi}]^2 × (5×10^{-2})\)
a = 5 m/s2