If \(\frac{4(\frac{2x}{5}-\frac{3}{2})}{3}\)+\(\frac{7}{5}\)=\(\frac{37}{5}\), then find the value of x2.
Answer & explanation
Correct answer: option 3
\(\frac{\frac{8x}{5}-6}{3}\)+\(\frac{7}{5}\)=\(\frac{37}{5}\)
\(\frac{8x-30}{5×3}\)+\(\frac{7}{5}\)=\(\frac{37}{5}\)
\(\frac{8x-30}{15}\) = \(\frac{30}{5}\)
x = 15
x2 = 225