If \(\frac{4(\frac{2x}{5}-\frac{3}{2})}{3}\)+\(\frac{7}{5}\)=\(\frac{37}{5}\), then find the value of x2.

144 169 225 256

225

\(\frac{\frac{8x}{5}-6}{3}\)+\(\frac{7}{5}\)=\(\frac{37}{5}\) \(\frac{8x-30}{5×3}\)+\(\frac{7}{5}\)=\(\frac{37}{5}\) \(\frac{8x-30}{15}\) = \(\frac{30}{5}\) x = 15 x2 = 225