Three persons A, B and C, fire a target in turn. Their probabilities of hitting the target are 0.3,0.5 and 0.2 respectively, the probability that the target hit is

0.72

$\text{P(A hits)=0.3}$

$\text{P(B hits)=0.5}$

$\text{P(C hits)=0.2}$

$\text{P(A misses)=1-0.3=0.7}$

$\text{P(B misses)=1-0.5=0.5}$

$\text{P(C misses)=1-0.2=0.8}$

$∴\text{P(No hit)}=0.7×0.5×0.8=0.28$

$\text{P(Hit)=1-P(No hit)}$

$=1-0.28=0.72$