Three persons A, B and C, fire a target in turn. Their probabilities of hitting the target are 0.3,0.5 and 0.2 respectively, the probability that the target hit is
Answer & explanation
Correct answer: option 3
$\text{P(A hits)=0.3}$
$\text{P(B hits)=0.5}$
$\text{P(C hits)=0.2}$
$\text{P(A misses)=1-0.3=0.7}$
$\text{P(B misses)=1-0.5=0.5}$
$\text{P(C misses)=1-0.2=0.8}$
$∴\text{P(No hit)}=0.7×0.5×0.8=0.28$
$\text{P(Hit)=1-P(No hit)}$
$=1-0.28=0.72$