Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Ratios

Question:

If a : b : c = 3 : 2 : 4 and b : d = 2 : 3, then find the value of $\left(\frac{a+c+d}{c-d}\right)^3$.

Options:

729/8

216

1000

1000/27

Correct Answer:

1000

Explanation:

a : b : c = 3 : 2 : 4

b : d = 2 : 3

= $\left(\frac{a+c+d}{c-d}\right)^3$

= $\left(\frac{3x+4x+3x}{4x-3x}\right)^3$.

= $\left(\frac{10x}{1x}\right)^3$

= \( {10 }^{3 } \) = 1000.