Two circles of radius 15cm and 13cm intersect at points P and Q. If PQ = 24cm; then distance between centers of the circle is:
Answer & explanation
Correct answer: option 3
(Chord is bisected by line through centre)
PR = \(\frac{1}{2}\) PQ
OP = 15 cm
O'P = 13 cm
Using Pythagoras theorem, triplets can be used : (9, 12, 15) & (5, 12, 13)
In Δ OPR ⇒ OR = 9 cm
In Δ OPR ⇒ O'R = 5 cm
Hence,
Distance between two centers (OO') = OR + O'R = 9 + 5 = 14 cm