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For a Poisson distribution, find $P(2)$, given $λ = 1$. |
0.232 0.184 0.152 1.025 |
0.184 |
The correct answer is Option (2) → 0.184 For a Poisson distribution, $P(r) =\frac{λ^re^{-λ}}{r!}$ $P(2)=\frac{1^2.e^{-1}}{2!}=\frac{0.368}{2}$ [$∵e^{-1}=0.368$, from table] $= 0.184$ |
