A charge Q is uniformly distributed over a large plastic plate. The electric field at point P, close to the centre of the plate is 10Vm^-1  . If the plastic plate is replaced by a copper plate of the same dimensions and carrying same charge Q then the electric field at the point P will be

10Vm^-1 

$\text{In both cases } E = \frac{\sigma}{\epsilon_0} = 10V/m$