A ball is dropped from a height of 1 m. If the coefficient of restitution between the surface and ball is 0.6, the ball rebounds to a height of :
Answer & explanation
Correct answer: option 4
Given : \(h_1 = 1 \text{ m } \)
Coefficient of restitution : \(e = \frac{v_2}{v_1} = 0.6\)
As : \(\frac{h_2}{h_1} = [\frac{v_2}{v_1}]^2\)
= \(0.6^2 = 0.36\)
\(h_2 = 0.36 h_1 = 0.36 \text{ m}\)