A ball is dropped from a height of 1 m. If the coefficient of restitution between the surface and ball is 0.6, the ball rebounds to a height of :

1 m 0.6 m 0.4 m 0.36 m

0.36 m

Given : \(h_1 = 1 \text{ m } \) Coefficient of restitution : \(e = \frac{v_2}{v_1} = 0.6\) As : \(\frac{h_2}{h_1} = [\frac{v_2}{v_1}]^2\)   = \(0.6^2 = 0.36\) \(h_2 = 0.36 h_1 = 0.36 \text{ m}\)