A, B and C can individually complete a task in 24 days, 20 days and 18 days, respectively. B and C start the task, and they work for 6 days and leave. The number of days required by A alone to finish the remaining task, is:
Answer & explanation
Correct answer: option 3
A = 24 days,
B = 20 days,
C = 18 days,
⇒ B + C worked for 6 days = (18 + 20) x 6 = 38 x 6 = 228 units ..(Efficiency × Days = Total work)
⇒ Remaining work = 360 - 228 = 132 units.
⇒ Time required by A to complete 132 units of work = \(\frac{132}{15}\) = \( { 8}_{ 15}^{12 }\) = \( { 8}_{ 5}^{4 }\) days. ..(\(\frac{Work}{Efficiency}\) = Time)