What is the value of remainder when 987 +876 + 765 + 654 + 543 + 432…

The correct answer is option (1) : 0

$987 = 3(mod\, 6)$

$876 =0(mod\, 6)$

$765= 3(mod\, 6)$

$654= 0(mod\, 6)$

$543= 3(mod\, 6)$

$432= 0(mod\, 6)$

$210= 0(mod\, 6)$

$≡(987 + 876 + 765 + 654 + 543 + 432 + 321 + 210) mod\, 6$.

$≡(3+ 0+3+0+3+0+3+0) mod\, 6$

$≡12\, mod\, 6$

$≡0\, mod\, 6$

Hence, remainder when

$(987 + 876 + 765 + 654 + 543 + 432 + 321 + 210) $ is divided by 6 = 0.