Three resistors of resistances \( 2\,\Omega \), \( 3\,\Omega \) and \( 5\,\Omega \) are connected in parallel and this combination is then connected to a battery of 10 V with negligible internal resistance. The potential difference across \( 3\,\Omega \) resistance will be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( 10\,\mathrm{V} \)
In a parallel combination every resistor is connected across the same two points, so each one has the same potential difference. The internal resistance of the battery is negligible, so there is no drop inside it and this common potential difference equals the emf.
\( V_{3\,\Omega} = V_{\mathrm{battery}} = 10\,\mathrm{V} \)
The resistor values only decide how the current divides (5 A, 10/3 A and 2 A) and play no part in the potential difference.
Note: The same question was also asked in CUET (UG) 2023 on 14-06-2023 (Slot 1).