The frustum of a right circular cone has the radius of the base as 5 cm, radius of the top as 3 cm, and height as 6 cm. What is its volume?
Answer & explanation
Correct answer: option 1
We know that,
Volume of Frustum (V) = \(\frac{1}{3}\)πH(R2+Rr+r2)
We have,
Radius of the base (R) = 5 cm
Radius of the top (r) = 3 cm
Height (H) of frustum = 6 cm
So,
Volume of Frustum = \(\frac{1}{3}\)π× 6 × [(5)2 + (5 × 3) + (3)2]
= V = π × 2 × [25 + 15 + 9]
= V = π × 2 × [49] = 98π cm3