The frustum of a right circular cone has the radius of the base as 5 cm, radius of the top as 3 cm, and height as 6 cm. What is its volume?

98 π cm³

We know that,

Volume of Frustum (V) = \(\frac{1}{3}\)πH(R²+Rr+r²)

We have,

Radius of the base (R) = 5 cm 

Radius of the top (r) = 3 cm

Height (H) of frustum = 6 cm

So,

Volume of Frustum = \(\frac{1}{3}\)π× 6 × [(5)² + (5 × 3) + (3)²]

= V = π × 2 × [25 + 15 + 9]

= V = π × 2 × [49] = 98π cm³