If the kinetic energies of an electron, an alpha particle and a proton is E1, E2 and E3 respectively with same de Broglie wavelength, then what will be the relation between these energies? |
E1>E2>E3 E1<E2<E3 E3>E1>E2 E1=E2=E3 |
E1=E2=E3 |
The relation between de Broglie wavelength and kinetic energy is given by \(\lambda \)=\(\frac{h}{2mK}\) So, if \(\lambda \) is same for all the particles, their kinetic energies will also be same i.e. E1=E2=E3. |