Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Dual Nature of Radiation and Matter

Question:

If the kinetic energies of an electron, an alpha particle and a proton is E1, E2 and E3 respectively with same de Broglie wavelength, then what will be the relation between these energies?

Options:

 E1>E2>E3 

 E1<E2<E3 

 E3>E1>E2 

 E1=E2=E3 

Correct Answer:

 E1=E2=E3 

Explanation:

The relation between de Broglie wavelength and kinetic energy is given by 

\(\lambda \)=\(\frac{h}{2mK}\)

So, if \(\lambda \) is same for all the particles, their kinetic energies will also be same i.e. E1=E2=E3.