Set A has 3 elements and the set B has 4 elements. Then the number of injective mappings that can be defined from A to B is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) - 24
No. of injective mappings = select any 3 from set B × No. of ways to arrange them in front of A
$={^4C}_3×3!$
$=24$